-16x^2-23x=-6

Solution for -16x^2-23x=-6 equation:

-16x^2-23x=-6

We move all terms to the left:

-16x^2-23x-(-6)=0

We add all the numbers together, and all the variables

-16x^2-23x+6=0

a = -16; b = -23; c = +6;
Δ = b2-4ac
Δ = -232-4·(-16)·6
Δ = 913
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-23)-\sqrt{913}}{2*-16}=\frac{23-\sqrt{913}}{-32}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-23)+\sqrt{913}}{2*-16}=\frac{23+\sqrt{913}}{-32}
$